6p^2-23-35=0

Solution for 6p^2-23-35=0 equation:

6p^2-23-35=0

We add all the numbers together, and all the variables

6p^2-58=0

a = 6; b = 0; c = -58;
Δ = b2-4ac
Δ = 02-4·6·(-58)
Δ = 1392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1392}=\sqrt{16*87}=\sqrt{16}*\sqrt{87}=4\sqrt{87}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{87}}{2*6}=\frac{0-4\sqrt{87}}{12}
=-\frac{4\sqrt{87}}{12}
=-\frac{\sqrt{87}}{3}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{87}}{2*6}=\frac{0+4\sqrt{87}}{12}
=\frac{4\sqrt{87}}{12}
=\frac{\sqrt{87}}{3}
$